3c^2-22c+35=

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Solution for 3c^2-22c+35= equation:


Simplifying
3c2 + -22c + 35 = 0

Reorder the terms:
35 + -22c + 3c2 = 0

Solving
35 + -22c + 3c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(7 + -3c)(5 + -1c) = 0

Subproblem 1

Set the factor '(7 + -3c)' equal to zero and attempt to solve: Simplifying 7 + -3c = 0 Solving 7 + -3c = 0 Move all terms containing c to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -3c = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -3c = 0 + -7 -3c = 0 + -7 Combine like terms: 0 + -7 = -7 -3c = -7 Divide each side by '-3'. c = 2.333333333 Simplifying c = 2.333333333

Subproblem 2

Set the factor '(5 + -1c)' equal to zero and attempt to solve: Simplifying 5 + -1c = 0 Solving 5 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1c = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1c = 0 + -5 -1c = 0 + -5 Combine like terms: 0 + -5 = -5 -1c = -5 Divide each side by '-1'. c = 5 Simplifying c = 5

Solution

c = {2.333333333, 5}

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